Generate random number

John Nerge

15. August 2018 19:28

Wondering if it's possible to generate a random number within a workflow? I tried this bit of code I found on StackOverflow, but within Workflow Designer it says that Rnd isn't declared and may be inaccessible due to its protection level

 

CInt(Math.Ceiling(Rnd() * 10)) + 1

 

Not a VB pro here, am I even on the right track?

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  Nico Burgerhart

  15. August 2018 19:36

  CInt(Math.Ceiling(Microsoft.VisualBasic.Rnd() * 10)) + 1

   

   

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  John Nerge

  15. August 2018 19:39

  Thanks, Nico!

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  Nico Burgerhart

  15. August 2018 19:39

  Or CInt(Math.Ceiling(Microsoft.VisualBasic.VBMath.Rnd() * 10)) + 1

   

   

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  Berend Veldkamp

  21. August 2018 13:12

  Personally I'd skip the VB reference altogether and use the default Random class (https://docs.microsoft.com/en-us/dotnet/api/system.random) . It has a bit more options, such as the returned type (float or integer), and passing of minimum and maximum values: New System.Random().Next(1, 10)

   

   

   

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  John Nerge

  21. August 2018 13:19

  Super cool, thanks!

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