Zum Hauptinhalt gehen

Has someone already worked with the forEach method ?

Kommentare

2 Kommentare

  • Bryan Bingham

    @Guillaume Ruelle? Did you ever get this working, and if so, could you please provide an example?

    0
  • Guillaume Ruelle

    @Bingham, Bryan? I didn't figure out how to do that. But I actually managed to use others JS method in other expressions like :

     

    =$SelectionCollection.result.push({feat: $QueryLayer.results, name: $QueryLoop.item.name, count:$QueryLayer.features.length})

     

    =$MainForm.state.ResultPicker.value.items.map(fs => fs.value)

     

    If you find a way, thx for letting me know !

     

    Regards,

    Guillaume

    0

Bitte melden Sie sich an, um einen Kommentar zu hinterlassen.